36y^2-196-11=0

Solution for 36y^2-196-11=0 equation:

36y^2-196-11=0

We add all the numbers together, and all the variables

36y^2-207=0

a = 36; b = 0; c = -207;
Δ = b2-4ac
Δ = 02-4·36·(-207)
Δ = 29808
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{29808}=\sqrt{1296*23}=\sqrt{1296}*\sqrt{23}=36\sqrt{23}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{23}}{2*36}=\frac{0-36\sqrt{23}}{72}
=-\frac{36\sqrt{23}}{72}
=-\frac{\sqrt{23}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{23}}{2*36}=\frac{0+36\sqrt{23}}{72}
=\frac{36\sqrt{23}}{72}
=\frac{\sqrt{23}}{2}
$